7m^2+2m-10=0

Solution for 7m^2+2m-10=0 equation:

7m^2+2m-10=0

a = 7; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·7·(-10)
Δ = 284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{284}=\sqrt{4*71}=\sqrt{4}*\sqrt{71}=2\sqrt{71}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{71}}{2*7}=\frac{-2-2\sqrt{71}}{14}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{71}}{2*7}=\frac{-2+2\sqrt{71}}{14}
$